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liesnalibis View Drop Down
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    Posted: Dec 24 2013 at 2:51am
Help a sista out. Embarrassed

Is there a way to get    V^2=PR    from    P=I^2*R     if      V=IR?      Also,   P=IV

Let me know if that makes sense. I know all the formulas are tru but I'm trying to cut down on the number of formulas I have to memorize.
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liesnalibis View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote liesnalibis Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 3:03am
More clarification--I'm trying to use algebra and these equations: "V=IR", "P=IV", and "P=I^2*R" to get "V^2/R". 

I'm trying to remember only the necessary equations and manipulate them to work different problems given different information so I don't confuse myself. I think that would help me understand more than remembering every form of every equation would.
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_ConcreteRose_ View Drop Down
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Post Options Post Options   Thanks (3) Thanks(3)   Quote _ConcreteRose_ Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 3:12am
Yes!
P=IV
V=IR
So first we want them both in V= form. one of them already is, so let's get the other on
P=IV (divide I from both sides) you get
P/I =V
and just flip it around
V=P/I

now you have to equations in V= form. Now how do you get V^2 from V.
well V^2 is just VxV. So multiply the two V's
VxV= (P/I)(IR)
now simplify
V^2 =PR
-----------------------------------------------------------------------------------------------------------------------------




and this is not important to answering the question but just to make sure, let's show that P=IV and V=IR can be written as P=I^2R
P=IV
V=IR
well this is true because so you replace the first V with the Second V
P=I(IR)
P=I^2R

---------------------------------------------------------------------------------

So in conclusion. We can go from P=I^2R to V^2=PR by using the two formulas V=IR and P=IV


Edited by _ConcreteRose_ - Dec 24 2013 at 3:14am
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liesnalibis View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote liesnalibis Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 3:20am
Originally posted by _ConcreteRose_ _ConcreteRose_ wrote:

Yes!
P=IV
V=IR
So first we want them both in V= form. one of them already is, so let's get the other on
P=IV (divide I from both sides) you get
P/I =V
and just flip it around
V=P/I

now you have to equations in V= form. Now how do you get V^2 from V.
well V^2 is just VxV. So multiply the two V's
VxV= (P/I)(IR)
now simplify
V^2 =PR
-----------------------------------------------------------------------------------------------------------------------------




and this is not important to answering the question but just to make sure, let's show that P=IV and V=IR can be written as P=I^2R
P=IV
V=IR
well this is true because so you replace the first V with the Second V
P=I(IR)
P=I^2R

---------------------------------------------------------------------------------

So in conclusion. We can go from P=I^2R to V^2=PR by using the two formulas V=IR and P=IV

OMGGGGG thanks! I'm goint to save this link and copy this in my book! Handshake

And the bolded, I would have NEVER thought of that.
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_ConcreteRose_ View Drop Down
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Post Options Post Options   Thanks (1) Thanks(1)   Quote _ConcreteRose_ Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 3:21am
No Prob. Glad I could help!
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Joja1107 View Drop Down
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Post Options Post Options   Thanks (7) Thanks(7)   Quote Joja1107 Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 6:16am
I'm a long time lurker...but I just wanted to say that I admire CR for helping ppl. I've never been good at math and it's always nice to see that ppl can call on you for help! Tis all..Embarrassed
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tatee View Drop Down
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Post Options Post Options   Thanks (1) Thanks(1)   Quote tatee Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 6:41am
i need to brush up my math skills.  at least i know who to go to nowLOL Thumbs Up
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_ConcreteRose_ View Drop Down
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Post Options Post Options   Thanks (1) Thanks(1)   Quote _ConcreteRose_ Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 6:48am
Joja. Thanks . I really just enjoy it.
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bindy View Drop Down
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Post Options Post Options   Thanks (1) Thanks(1)   Quote bindy Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 6:53am
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_ConcreteRose_ View Drop Down
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Post Options Post Options   Thanks (8) Thanks(8)   Quote _ConcreteRose_ Quote  Post ReplyReply Direct Link To This Post Posted: Dec 24 2013 at 6:54am
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